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Differences between revisions 5 and 7 (spanning 2 versions)
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$ \large { E = \frac{1}{2} V S_{max} } $ . . . half the hoop volume times the maximum tensile stress. $ \large { E = {1 \over 2} V S_{max} } $ . . . half the hoop volume times the maximum tensile stress.
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Real flywheels will have rotating structure that does not contribute to this strength, and flywheels thicker than a thin shell will have inner material at less than maximum stress and storing less than maximum energy. So the simple energy equation above is overoptimistic; if you include the container, the empty volume, the axial motor, the magnetic bearings, a decent safety factor, etc, then the maximum stored energy may be a small fraction of this maximum . also, $ E = {1 \over 2} \rho V v^2 = {1 \over 2} V S_{max}, so

$ \large { v^2 = S_{max} / \rho } $

Real flywheels will have rotating structure that does not contribute to this strength, and flywheels thicker than a thin shell will have inner material at less than maximum stress and storing less than maximum energy. So the simple energy equation above is overoptimistic; if you include the container, the empty volume, the axial motor, the magnetic bearings, a decent safety factor, etc, then the maximum stored energy may be a small fraction of this maximum .  The maximum rim velocity, hence the maximum energy per flywheel mass, is similarly constrained.

Beacon Power flywheel maximum speeds are 670 meters per second; perhaps in time they may learn how to reliably increase this to 1000 meters per second. This will require defect-free manufacturing, and careful attention to stress management around yarn ends and voids in the binder matrix of the carbon fiber materials. I wish them the best of luck.

Power Loop for SusTech Notes


Flywheel Scaling

The fastest possible non-magnetic flywheel is a thin hoop of material at maximum stress. Assume a thin flywheel hoop rotating around a vertical axis, with radius r, cross section A, made of a material with a mass density of and maximum tensile strength Smax. The mass of the whole loop is 2rA, and the volume is V=2rA.

If the flywheel rotates at angular frequency , the rim velocity v=r, and the stored energy is

E=r3A2. The maximum usable energy is a (hopefully large) fraction of that.

Consider a small element d of the hoop, where is the position around the loop. If the hoop is circumferential stress is Sc, then we can construct a force triangle where the deflection of the circumferential force is ScAd2  at each end, for a total centripedal force of ScAd . This is balanced by the centrifugal acceleration of the element, dMa=(rAd)(2r). So:

ScAd=r2A2d

Sc=r22

At maximum stress, r22=Smax  . . . Plugging this into the stored energy equation, we get:

E=rA(r22)=rA(Smax)=rASmax 

E=21VSmax  . . . half the hoop volume times the maximum tensile stress.

also, $ E = {1 \over 2} \rho V v^2 = {1 \over 2} V S_{max}, so

v2=Smax 

Real flywheels will have rotating structure that does not contribute to this strength, and flywheels thicker than a thin shell will have inner material at less than maximum stress and storing less than maximum energy. So the simple energy equation above is overoptimistic; if you include the container, the empty volume, the axial motor, the magnetic bearings, a decent safety factor, etc, then the maximum stored energy may be a small fraction of this maximum . The maximum rim velocity, hence the maximum energy per flywheel mass, is similarly constrained.

Beacon Power flywheel maximum speeds are 670 meters per second; perhaps in time they may learn how to reliably increase this to 1000 meters per second. This will require defect-free manufacturing, and careful attention to stress management around yarn ends and voids in the binder matrix of the carbon fiber materials. I wish them the best of luck.


PowerLoopSusTech (last edited 2023-12-31 02:27:58 by KeithLofstrom)