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| The loop calculation is fairly simple - an 80 kilometer breech altitude launch loop defines a transfer orbit with a perigee $ r_p $ = 6378 + 80 km = 6458 km . The semimajor axis is $ a = 0.5 * ( r_p + r_d ) $, the eccentricity $ e = ( r_d - r_p ) / ( r_d + r_p ) $, the characteristic velocity is $ v_0 = \sqrt{ \mu / ( a * ( 1 - e^2 ) ) }, and the apogee velocity is $ v_a = ( 1 - e ) v_0 $. Combining and simplifying: | The loop calculation is fairly simple - an 80 kilometer breech altitude launch loop defines a transfer orbit with a perigee $ r_p $ = 6378 + 80 km = 6458 km . The semimajor axis is $ a = 0.5 * ( r_p + r_d ) $, the eccentricity $ e = ( r_d - r_p ) / ( r_d + r_p ) $, the characteristic velocity is $ v_0 = \sqrt{ \mu / ( a * ( 1 - e^2 ) ) } $ , and the apogee velocity is $ v_a = ( 1 - e ) v_0 $. Combining and simplifying: |
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| $ {v_a}^2 = ( 2 \mu r_p ) / ( r_a ( r_d + r_p ) ) $ | $ {v_a}^2 = ( 2 \mu r_p ) / ( r_d ( r_d + r_p ) ) $ |
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| $ v_a = \sqrt{ ( 2 \mu r_p ) / ( r_a ( r_d + r_p ) ) } $ | $ v_a = \sqrt{ ( 2 \mu r_p ) / ( r_d ( r_d + r_p ) ) } $ |
Orbit Circularization
What is the ΔV needed for apogee insertion into a circular equatorial orbit from a launch loop transfer orbit, and for perigee insertion from a space elevator transfer orbit?
The destination orbit has a radius of 
rd =
The loop calculation is fairly simple - an 80 kilometer breech altitude launch loop defines a transfer orbit with a perigee 
5
(rp+rd)(rd+rp) (a(1−e2))
a)(1−e)2(1−e2)
{v_a}^2 = ( 2 \mu r_p ) / ( r_d ( r_d + r_p ) )
v_a = \sqrt{ ( 2 \mu r_p ) / ( r_d ( r_d + r_p ) ) }
\Delta V = v_d - v_a