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The scattering from a single resonator at frequency $ ~ \large \omega ~ $ is (from Feynman Lectures on Physics page 32-6 ) proportional to: The scattering cross section from a single resonator at frequency $ ~ \large \omega ~ $ is derived from [[ http://www.feynmanlectures.caltech.edu/I_32.html | Feynman Lectures on Physics, volume one, chapter 32, page 6 ]], and is proportional to:

Rayleigh Scattering of Isolated Species

( Species == ions, atoms, molecules )

  • See Polarization for the low wavenumber (frequency / speed of light ) approximation used for Rayleigh scattering.

Scattering is due to the polarization of species. The polarization can be summed from the behavior of individual resonances and damping factors (related to resonance bandwidth), which I have not yet been able to find. For mostly-isolated atoms in high vacuum, Beers line broadening will not be relevant; the bandwidth ~ \large \gamma ~ is related to damping time, TBD

  • note: perhaps I can get the relevant numbers from HITRAN, but many of the resonances (especially for tightly bound molecules and deep atomic orbitals) will be far into the ultraviolet, where HITRAN may not go. TBD


The scattering cross section from a single resonator at frequency ~ \large \omega ~ is derived from Feynman Lectures on Physics, volume one, chapter 32, page 6, and is proportional to:

{ \huge \int } { \Large { \omega^4 \over { ( \omega^2 ~-~ \omega_0^2 )^2 ~+~ \gamma^2 \omega^2 } } ~ } { d \omega } ~=~~~~ { \Large \omega ~~ + } ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ { { \large \left( 2 \omega_0^4 ~+~ 2 \omega_0^2 \gamma \left( \sqrt{ \gamma^2 ~-~ 4 \omega_0^2 } ~-~ 2 \gamma \right) ~+~ \gamma^3 \left( \gamma - \sqrt{ \gamma^2 ~-~ 4 \omega_0^2 } \right) \right) ~~ \tan^{-1} \left( { \Large { { \huge \omega } \over { \sqrt{ { \Large { \gamma \over 2 } } \left( \gamma ~-~ \sqrt{ \gamma^2 ~-~ 4 \omega_0^2 } \right) ~-~ \omega_0^2 } } } } \right) } \over { \large \sqrt{ 2 } ~ \gamma ~ \sqrt{ \gamma^2 ~-~ 4 \omega_0^2 } ~ \sqrt{ \gamma ~ \left( \gamma ~-~ \sqrt{ \gamma^2 ~-~ 4 \omega_0^2 } \right) ~-~ 2 \omega_0^2 } } } ~~ {\Large - } { { \large \left( 2 \omega_0^4 ~-~ 2 \omega_0^2 \gamma \left( \sqrt{ \gamma^2 ~-~ 4 \omega_0^2 } ~+~ 2 \gamma \right) ~+~ \gamma^3 \left( \gamma + \sqrt{ \gamma^2 ~-~ 4 \omega_0^2 } \right) \right) ~~ \tan^{-1} \left( { \Large { { \huge \omega } \over { \sqrt{ { \Large { \gamma \over 2 } } \left( \gamma ~+~ \sqrt{ \gamma^2 ~-~ 4 \omega_0^2 } \right) ~-~ \omega_0^2 } } } } \right) } \over { \large \sqrt{ 2 } ~ \gamma ~ \sqrt{ \gamma^2 ~-~ 4 \omega_0^2 } ~ \sqrt{ \gamma ~ \left( \gamma ~+~ \sqrt{ \gamma^2 ~-~ 4 \omega_0^2 } \right) ~-~ 2 \omega_0^2 } } }

Using Wolfram alpha for the integration, and slightly reordered for visual symmetry.

A frightening number of radicals that could contain negative values, depending on the values of \omega_0 and \gamma ; we do know that \omega_0 > \gamma > 0 , which suggests a heap of complex numbers.


So, let's cheat. The solar irradiance data I have is actually in terms of wavelength; nanometers, not Terahertz. The wavelength \lambda = 2 \pi c / \omega ; let's derive the cross section in terms of wavelength.

The actual equation will be a long series of many such terms, one per resonance. And it will really be computed with a C program, which iterates over the resonances, then over the frequency bins and values for the average vacuum solar spectrum. Much information missing, many opportunities for mistakes, and a serious lack of empirical data to compare it with.

rayleigh (last edited 2019-09-21 06:23:24 by KeithLofstrom)