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==== So ... don't do it that way. ====  == So ... don't do it that way. == 
SBSPplume
Some advocate sourcing all the world's energy with spacebased solar power (SBSP), on the order of 30 Terawatts. They suggest space solar power satellite (SSPS) masses on the order of 4 kg / kW, or 0.004 kg per watt. That works out to 4e3 kg/W * 3e13 W or 120e9 kg of SSPS mass delivered to Geostationary Orbit ( GEO, 42164 km radius, 3075 m/s ). This does not include construction equipment or stationkeeping fuel.
Modern comsats use noblegas electric thrusters to climb to GEO. This is propellantthrifty; however, this has driven up the price of Xenon and is shifting to Krypton. There is not enough available highZ noble gas (xenon, krypton) to raise the orbits of 120 million of tonnes of power satellite. There is plenty of argon, but that must be chilled below 27 Kelvin to store densely for the long trip to GEO.
The transfer orbit, and GEO injection velocity
So, consider liquid hydrogen/liquid oxygen ( LH/LOX) chemical rockets, with typical 1:6 mass ratio (slightly fuel rich), producing a propellant plume of and H₂ and H. The mass ratio of water to total hydrogen ( H₂ plus H ), assuming complete combustion and no hydroxyl ( OH or HO ) or hydronium ( H₃O ).
Assuming a high expansion vacuum nozzle, the exhaust velocity of a liquid hydrogen engine might be as high as 4460 m/s.
Spacecraft typically launch to GEO from low earth orbit (LEO) via a geostationary transfer orbit (GTO). Presume that the GTO perigee starts from a 122 km equatorial altitude so that the GTO is an ellipse with perigee = 6500 km, apogee = 42164 km, semimajor axis 24332 km. The apogee velocity of the GTO ellipse is 1589 m/s. The GEO circularization delta V is (30751589) = 1486 m/s .
Presuming an exhaust velocity of 4460 m/s, and a delta V of 1486 m/s, the plume mass can be calculated using the Tsiolkovsky equation:
M_{plume} = M_{delivered} \times ( e^{ \Delta V / V_e }  1 ) = 120e9 kg × ( exp( 1486 / 4460 )  1 ) = 120e9 kg × 0.395 = 47e9 kg.
The plume will be emitted in a retrograde direction from the vehicle as it accelerates from 1589 to 3075 m/s ; the plume velocity will range from (44601589) m/s to (44603075) m/s retrograde, or 2871 m/s to 1385 m/s.
What happens to the plume??
Even with a high expansion nozzle, the plume will be hot, with significant Maxwellian thermal velocity. Some species (molecules, atoms, ions) will travel more slowly than average, some faster. But let's ignore that to start with, and assume the gas molecules are all in retrograde elliptical orbits. What are the perigees of those orbits?
Well, to start with, we know a retrograde orbit with a velocity of 1589 m/s has a perigee of 122 km; slower species will descend to a lower altitude and fall into the atmosphere. Species with a retrograde velocity of 2871 m/s will have an perigee of 32600 km, and will remain above the atmosphere for a very long time. Species with a retrograde velocity of 1640 m/s will have a perigee above 600 km, and will remain in orbit for decades.
Lets consider the portion of the plume emitted between 1640 m/s and 2871 m/s to be in semipermanent orbits, and the portion of the plume emitted between 1589 m/s and 1640 m/s to reenter and stop being a problem. If the plume is 1640 m/s retrograde, the vehicle is travelling 44601640 = 2820 m/s prograde. So, the reentering portion of the plume is the fraction emitted while the vehicle accelerates from 2820 to 3075 m/s, a delta V of 255 m/s. Let's use the Tsiolkovsky equation for that:
M_{entry} = M_{delivered} \times ( e^{ \Delta V / V_e }  1 ) = 120e9 kg × ( exp( 255 / 4460 )  1 ) = 120e9 kg × 0.0588 = 7e9 kg.
So, the plume emitted into semipermanent orbits is (477)e9 = 40e9 kg.
Orbits with an apogee at GEO! Over those years, most of those species will collide with the ram (forward orbit facing) surfaces of the SSPS, at velocities up to 5946 m/s (3075 + (44601589)) slowing them and sputtering the ram surface. An H₂O molecule with a mass of 18 AMU (3e26 kg) and a relative velocity of 5946 m/s has a kinetic energy of 5.3e19 J or 3.3 electron volts. For comparison, monatomic oxygen in 500 km LEO ( orbit speed has a kinetic energy of 7.719 J or 4.8 eV, is vastly less dense, and is a known long term hazard to much denser objects than an SSPS.
This is an "N squared" problem. Delivering 1500 tonnes of GEO comsat with a 500 tonnes of propellant plume is a 6400 times smaller problem. The comsats are much denser than an SSPS, reducing the collision cross section. We have not encountered any major problems yet  unless plume collision erosion is responsible for a few unexplained losses ...
So ... don't do it that way.
Alternatives include arrival from ABOVE, construction in Highly Elliptical Earth Orbits (HEEO). HEEO arrival and apogee velocities are slower, delta V's are smaller, and the plumes are launched to escape. The slow relative arrival velocity permits semipassive vehicles and nonrocket capture systems (tailhooks! nets!) with the capture station restoring momentum using permanent highISP electric thrusters, perhaps using plentiful argon propellant frequently resupplied from the ground. Much more delta V is needed to raise perigee to GEO (again from a very high apogee with a relatively small Earth escape velocity). Arriving at GEO, more retrograde thrust is needed, but the propellant plume is launched forwards, faster than Earth escape velocity.
Of course, higher ISP electric engines for a LEO to GEO spiral orbit will also launch their propellant plumes retrograde, much faster than escape. However, not all electric engines are created equal; if the bell expansion is small or absent, the plumes will have high thermal velocities, and a significant fraction of the plume species will go into permanent orbits; some with high apogees, meaning they could arrive at the ram surface of the SSPS with more than double GEO orbit velocity, nearlt as fast as the relative speed for atomic oxygen at the ram surface of GEO objects.
The fraction will be smaller ... this is good ... but it would be better to make it MUCH smaller with careful plume management.