Differences between revisions 6 and 14 (spanning 8 versions)
 ⇤ ← Revision 6 as of 2018-11-05 17:03:30 → Size: 53 Editor: KeithLofstrom Comment: ← Revision 14 as of 2020-04-18 23:01:44 → ⇥ Size: 14583 Editor: KeithLofstrom Comment: change to pointer to ServerSky page Deletions are marked like this. Additions are marked like this. Line 1: Line 1: #refresh 1 http://server-sky.com/NearCircularOrbits ## page was renamed from NearCircularOrbits#format jsmath= Near Circular Orbits =-----== General Elliptical Orbits ==In the orbital plane, neglecting the $J_2$ spherical oblateness parameter :||<-2:> '''circular orbits''' ||<|10-3>{{attachment:Anomaly.png|Drawing from Wikipedia|width=400}}|||| gravitational parameter || $\large \mu = a^3 \omega^2 = G M$ |||| semimajor axis || $\large a = \sqrt[3]{ \mu / \omega^2 }$ |||| angular velocity || $\large \omega = \sqrt{ \mu / a^3 }$ |||| sidereal period || $\large T = 2\pi / \omega = 2\pi \sqrt{ a^3/\mu }$ |||| $J_2$ Speedup factor || $\large \omega'/\omega = 1+1.5 |J_2| (R_{eq}/a)^2$ ||||<-2:> '''elliptical orbits''' |||| eccentricity || $\large e = ( r_a - r_p ) / ( r_a + r_p )$ |||| velocity || $\large v_0 = \LARGE\sqrt{\mu\over{a (1 - e^2)}} \large = \LARGE\sqrt{{\mu \over 2}\left({1 \over r_a}+{1 \over r_p}\right)}$ |||| true anomaly<
>orbit angle from focus|| $\Large \theta$ |||| eccentric anomaly<
>ellipse center angle||$\large E=\pm\arccos\Large\left({{e+\cos(\theta)}\over{1+e\cos(\theta)}}\right)$|| || periapsis || apoapsis |||| mean anomaly || $\large M = E - e \sin( E )$||<)> earth || perigee || apogee |||| time from perigee || $\large t = M / \omega$||<)> sun || perihelion || aphelion |||| radius || $\large r=a\Large{{1-e^2}\over{1+e\cos(\theta)}}$||<:>$\huge\rightarrow$||$\large r_p =( 1-e )a$||$\large r_a =( 1+e )a$|||| tangential velocity || $\large v_{\perp}= v_0 ( 1+e \cos( \theta ))$||<:>$\huge\rightarrow$||$\large v_p =(1+e)v_0$||$\large v_a =(1-e)v_0$|||| radial velocity || $\large v_r = e v_0 \sin( \theta )$||<:>$\huge\rightarrow$||$0$||$0$|||| total velocity<
>tangent to orbit|| $\Large v=\LARGE \sqrt{{{2\mu}\over{r}}-{{\mu}\over{a}}}$||<:>$\huge\rightarrow$||$\large v=v_p,~ r=r_p$||$\large v=v_a,~ r=r_a$|||| orbit energy parameter || $\large C_3=-\mu/a = -v_p v_a$||<-3:> $\large \mu= a v_p v_a ~~~~~~~~~ 2 a= r_p + r_a$|||| angular momentum || $\large L =\LARGE \sqrt{ { 2 \mu ~ r_a ~ r_p } \over { r_a + r_p } }$ || || $\large v_p = \LARGE \sqrt{ { 2 \mu ~ r_a } \over { r_p ( r_a + r_p ) } }$ || $\large v_a = \LARGE \sqrt{ { 2 \mu ~ r_p } \over { r_a ( r_a + r_p ) } }$ |||| semimajor axis || $\large a={\LARGE{{r_p+r_a}\over{2}}}={\LARGE{{r_p}\over{1-e}}}={\LARGE{{r_a}\over{1+e}}}$ || || $\large a = { \LARGE 1 \over { \huge { { 2 \over r_p } - { v_p^2 \over \mu } } } }$ || $\large a = { \LARGE 1 \over { \huge { 2 \over r_a } - { v_a^2 \over \mu } } }$|||| semilatus rectum || $\large l = \sqrt{ r_a r_p }$ || || || ||----=== Computing an orbit from an altitude and a velocity ===Assume an Earth orbit, given a radius $r$ and a velocity vector (speed $v$ elevation angle from tangential/horizontal $\beta$ such that the tangential velocity is $v_\perp ~ = ~ v \cos( \beta )$ ). The vector and the center of the Earth define a plane. Decompose the velocity vector into a radial and a tangential component in that plane. First, we find the semimajor axis:$\large a ~=~ { \huge { 1 \over { { 2 \over r } - { v^2 \over \mu } } } }$Next, compute the angular momentum:$\large L ~=~ r v ~ \cos( \beta )$ Compute the eccentricity:$\large e ~=~ \sqrt{ 1 - {\LARGE {{ L^2 } \over { \mu a }} } }$apoapse $~=~ \large ( 1 + e ) a ~~~~~~$ periapse $~=~ \large ( 1 - e ) a$----=== Changing perigee by changing apogee velocity ===$\large v_a^2 = 2 \mu \LARGE \left( { 1 \over r_a } - { 1 \over {r_a + r_p} } \right) ~ ~ ~ ~ ~ ~ \LARGE { { \partial v_a } \over { \partial r_p } } = { \mu \over { v_a ( r_a + r_p )^2 } } ~ ~ ~ ~ ~ ~$ for nearly circular orbits: $~ ~ ~ \LARGE { { \partial v } \over { \partial r } } \approx { v \over { 4 r } }$----=== Fictional Forces in Orbit ===In the rotating frame of a circular orbit, counterclockwise viewed from above the orbital plane, the directions are|| direction || unit vector || description |||| $x$ || $\vec i$ || Tangential to (along the line of) the orbit, in the orbital plane, pointing clockwise or westward |||| $y$ || $\vec j$ || Radially outwards from the center of rotation, in the orbital plane |||| $z$ || $\vec k$ || Perpendicular to the orbital plane, northwards ||The rotation is expressed as $\vec \Omega = \omega \vec k$, where $\omega$ is the angular velocity of the orbit .The radial vector $\vec r$ is composed of $\vec r = x \vec i + y \vec j + z \vec k$.Coriolis acceleration: $\large \ddot{\vec r}_{Coriolis} = -2 \vec \Omega \times \dot { \vec r }$Centrifugal acceleration: $\large \ddot{\vec r}_{Centrifugal} = - \vec \Omega \times \vec \Omega \times \vec r$FROM HERE DOWN, WORK IN PROGRESS, NOT VERIFIED: . note - these are probably the Hill-Clohessy-Wiltshire equationsCentripedal (gravity) acceleration: $\large \ddot{\vec r}_{Centripedal} = \omega^2 ( 2 y \vec k - x \vec i - z \vec j )$Scalar equations:$\large \ddot x = 2 \omega \dot y $$\large \ddot y = -2 \omega \dot x + 3 \omega^2 y$$ \large \ddot z = -\omega^2 z$----=== Locus of Elliptical Orbit Position in Rotating Frame ===For small eccentricities e, the deviation of the position of an object in a nearly circular eccentric orbit deviates from a ideal circular orbit as an ellipse, with a width of 4e and a height of 2e. This is difficult to compute analytically, but easy to show numerically. Here is a plot the normalized loci of the x,y position in the rotating frame, for various values of eccentricity:{{attachment:locus01.png}}[[attachment:locus01.pl | perl data generator]][[attachment:locus01.dat | locus data]][[attachment:locus01.gp | gnuplot command file]]If the whole orbit rotates east, clockwise when viewed from the north, then the object follows the locus above clockwise, with $\theta = 0$ at the bottom of the ellipsoid.The figure is very close to an ellipse for small e, but not exactly so. The program computes the radial distance rr, and the radial position xr and yr as a function of $\theta$. The program then computes the eccentric anomaly E, and the mean anomaly M. It then rotates the position vector back along the orbit, to approximately vertical,then subtracts the unit vector representing the elliptical orbit. So, it is approximately like watching an object in an elliptical orbit from a position in a circular orbit with the same semimajor axis. The deviation from an ellipse is quite small, until the eccentricity gets larger than 0.01 or so. Server sky orbits will have eccentricities of less than 0.002 .In the rotating frame, these eccentric loci describe the path of an object subject to fictitious forces. This provides an additional check on our equations for fictitious forces.----==== The math ====$\large \dot{ \theta } = v_{\perp} / r = v_0 ( 1+e \cos( \theta )) / ( a (1-e^2) / {1+e\cos(\theta)} $$\large \dot{ \theta } = ( \sqrt{ \mu / ( a (1 - e^2) ) } / a ( 1-e^2 ) ) ( 1 + e\cos( \theta ))^2$$\large \dot{ \theta } = ( \sqrt{ \mu / ( a^3 (1 - e^2)^3 ) } ( 1 + 2 e \cos( \theta ) + e^2 \cos( \theta )^2 )$for small perturbations, $e^2 \approx 0$, so$\large \dot{ \theta } \approx ( \sqrt{ \mu / a^3 } ( 1 + 2 e \cos( \theta ) )$In the rotating frame, $\dot{ x } \approx a ( \dot{ \theta } - \omega )$ where $\omega \equiv \sqrt{ \mu / a^3 }$, so$\large \dot{ x } \approx a \sqrt{ \mu / a^3 } ( ( 1 + 2 e \cos( \theta ) - 1 ) $$\large \dot{ x } \approx 2 e a \omega ( \cos( \theta ) ) Approximating \theta \approx \omega t , we can integrate to get:\Large x \approx -2 e a \sin( \theta ) ----\large \dot{ y } = v_r = e v_0 \sin( \theta ) \approx e a \omega \sin( \omega t ) Integrating:\Large y \approx -e a \cos( \theta ) For small e , these equations in y and x describe the locus calculated above.----==== Testing the Equations for Acceleration ==== \large \ddot x ~ ? = ~ \large 2 \omega \dot y$$ \large \ddot x = { { d^2 } \over { dt^2 } } ( -2 e a \sin( \theta ) ) = { d \over { dt } } ( -2 e a \omega \cos( \theta ) ) = \Large 2 e a \omega^2 \sin ( \theta ) $$\large 2 \omega \dot y = 2 \omega { d \over { dt } } -e a \cos( \theta ) = \Large 2 e a \omega^2 \sin ( \theta ) . . . equal! \large \ddot y ~ ? = ~ \large -2 \omega \dot x + 3 \omega^2 y$$ \large \ddot y = { { d^2 } \over { dt^2 } } ( -e a \cos( \theta ) ) = { d \over { dt } } ( e a \omega \sin( \theta ) ) = \Large e a \omega^2 \cos( \theta ) $$\large -2 \omega \dot x + 3 \omega^2 y = -2 \omega { d \over { dt } }( -2 e a \sin( \theta ) + 3 \omega^2 ( - e a \cos( \theta ) ) )$$ \large ~~~~~~~~~~~~~~= 4 e a \omega^2 \cos(\theta) - 3 e a \omega^2 \cos( \theta ) = \Large e a \omega^2 \cos( \theta )~~~$ ... equal!The acceleration equations work!----=== Periods of M orbits ===M orbits describe the number of minutes an orbit takes travel once around the earth and return to the same position overhead. For server sky, these are integer fractions of a 1440 minute synodic day; this makes it easier to calculate the sky position given the orbital parameters and the time of day. the M288 orbit returns to the same apparent position 5 times per day, or 365.256...*5 times per year. That position moves around the earth 365.256...+1 times per year. So the total number of orbits per year, relative to the stars, is 365.256...*6+1 orbits per year. That is divided into the year length in seconds to yield theM288 sidereal orbit time = ( 365.256... * 86400 ) / ( 365.256... * 6 + 1 ) = 86400 / ( 6 + 1/365.256... ) = 14393.43227 seconds1 year = 365.256363004 days of 86,400 seconds, or 31558149.7635456 seconds.J2 speedup fraction $= - 3 J_2 ( a_E / a )^2 = 3 \times 1.082626683e-3 \times (6378107m)^2 / a^2 = 1.321245688e11m^2 / a^2$----=== A Table of orbits ===|| || || LEO 300Km || M288 || M360 || GEO || Moon || Earth || units |||| $\mu$ || gravitation param. ||<:-5> 3.98600448e14 || 1.3271244e20 || m^3^/s^2^|||| ||<)> relative to ||<:-5> earth || Sun || |||| $J_2$ || Oblate-ness ||<:-5> -1.082626683e-3 earth radius = 6378107m || -6e-7 || ||||$\omega'/\omega$||J2 speedup fraction|| 2.9627e-3|| 8.0782e-4|| 6.3356e-4 || 7.4318e-5 || 8.9417e-7 || 2e-17 || |||| $a_g$ || gravity || 8.938095 || 2.437062 || 1.9113693 || 0.02242078 || 0.002697573|| 0.005930053 || s |||| $T$ || sidereal period || 5431.010 || 14393.4323 || 17270.5433 || 86164.100 || 2360591.577|| 31558149.76 || s |||| $T_s$ || synodic period || 5431.945 || 14400 || 17820 || 86400 || 2551442.9 || 31558149.76 || s |||| $T/2\pi$|| Sidereal / 2pi || 864.3721 || 2290.78585 || 2748.69228 || 13713.44093|| 375698.7212|| 5022635.5297|| s |||| $\omega$|| Angular velocity || 1.1569e-03|| 4.36531e-04|| 3.63809e-04|| 7.29212e-05|| 2.66171e-06|| 1.99099e-07 || rad/s |||| || orbits/year || 5810.733 || 2192.5382 || 1827.2819 || 366.25640 || 13.36879 || 1.00000 || |||| $a$ || semimajor axis || 6678000 || 12788971 || 14440980 || 42164170 || 384399000 || 1.4959826e11 || m |||| $R_a$ || apogee radius || 6678000 || 12838976 || 14440980 || 42164170 || 405696000 || 1.5209823e11 || m |||| $R_p$ || perigee radius || 6678000 || 12738976 || 14440980 || 42164170 || 363104000 || 1.4709829e11 || m |||| $e$ || eccentricity || 0.000000 || 0.001951 || 0.001728 || 0.000000 || 0.055401 || 0.016711 || |||| $V_0$ || mean velocity || 7725.84 || 5582.79 || 5253.76 || 3074.66 || 1023.16 || 29784.81 || m/s |||| $V_a$ || apogee velocity || 7725.84 || 5571.90 || 5244.68 || 3074.66 || 966.47 || 29287.07 || m/s |||| $V_p$ || perigee velocity || 7725.84 || 5593.68 || 5262.84 || 3074.66 || 1079.84 || 30282.55 || m/s |||| $C_3$ || orb. specific energy|| -59688597 || -31167516 || -27602035 || -9453535 || -1036945 || -887125553 || J/kg ||Note: This table uses the classic formula $\omega^2 a^3 = \mu$, and does not take into account the oblate spheroid shape of the Earth, and many other perturbations. However, with the perturbations included, and with good data from ground stations and GPS to establish positions and velocities, we really can compute these numbers to this many decimal places. So while the numbers above are actually far less accurate, they represent the precision of the measurements we will someday compute.The eccentricities for the M orbits assume orbits mapped onto a 50km minor radius toroid.[[ Lageos | LAGEOS 1 and LAGEOS 2 ]] are two slightly lower satellites in inclined but highly circular orbits.REFS: . http://articles.adsabs.harvard.edu/full/1981AJ.....86..912G . http://en.wikipedia.org/wiki/Rotating_reference_frame . http://en.wikipedia.org/wiki/Kepler_orbit . http://en.wikipedia.org/wiki/Kepler%27s_laws_of_planetary_motion . http://en.wikipedia.org/wiki/Orbital_period . http://en.wikipedia.org/wiki/Mean_anomaly . http://en.wikipedia.org/wiki/Eccentric_anomaly ... where I got the picture, then modified it----copied from http://server-sky.com/NearCircularOrbits

# Near Circular Orbits

## General Elliptical Orbits

In the orbital plane, neglecting the J_2 spherical oblateness parameter :

 circular orbits gravitational parameter \large \mu = a^3 \omega^2 = G M semimajor axis \large a = \sqrt[3]{ \mu / \omega^2 } angular velocity \large \omega = \sqrt{ \mu / a^3 } sidereal period \large T = 2\pi / \omega = 2\pi \sqrt{ a^3/\mu } J_2 Speedup factor \large \omega'/\omega = 1+1.5 |J_2| (R_{eq}/a)^2 elliptical orbits eccentricity \large e = ( r_a - r_p ) / ( r_a + r_p ) velocity \large v_0 = \LARGE\sqrt{\mu\over{a (1 - e^2)}} \large = \LARGE\sqrt{{\mu \over 2}\left({1 \over r_a}+{1 \over r_p}\right)} true anomaly orbit angle from focus \Large \theta eccentric anomaly ellipse center angle \large E=\pm\arccos\Large\left({{e+\cos(\theta)}\over{1+e\cos(\theta)}}\right) periapsis apoapsis mean anomaly \large M = E - e \sin( E ) earth perigee apogee time from perigee \large t = M / \omega sun perihelion aphelion radius \large r=a\Large{{1-e^2}\over{1+e\cos(\theta)}} \huge\rightarrow \large r_p =( 1-e )a \large r_a =( 1+e )a tangential velocity \large v_{\perp}= v_0 ( 1+e \cos( \theta )) \huge\rightarrow \large v_p =(1+e)v_0 \large v_a =(1-e)v_0 radial velocity \large v_r = e v_0 \sin( \theta ) \huge\rightarrow 0 0 total velocity tangent to orbit \Large v=\LARGE \sqrt{{{2\mu}\over{r}}-{{\mu}\over{a}}} \huge\rightarrow \large v=v_p,~ r=r_p \large v=v_a,~ r=r_a orbit energy parameter \large C_3=-\mu/a = -v_p v_a \large \mu= a v_p v_a ~~~~~~~~~ 2 a= r_p + r_a angular momentum \large L =\LARGE \sqrt{ { 2 \mu ~ r_a ~ r_p } \over { r_a + r_p } } \large v_p = \LARGE \sqrt{ { 2 \mu ~ r_a } \over { r_p ( r_a + r_p ) } } \large v_a = \LARGE \sqrt{ { 2 \mu ~ r_p } \over { r_a ( r_a + r_p ) } } semimajor axis \large a={\LARGE{{r_p+r_a}\over{2}}}={\LARGE{{r_p}\over{1-e}}}={\LARGE{{r_a}\over{1+e}}} \large a = { \LARGE 1 \over { \huge { { 2 \over r_p } - { v_p^2 \over \mu } } } } \large a = { \LARGE 1 \over { \huge { 2 \over r_a } - { v_a^2 \over \mu } } } semilatus rectum \large l = \sqrt{ r_a r_p }

### Computing an orbit from an altitude and a velocity

Assume an Earth orbit, given a radius r and a velocity vector (speed v elevation angle from tangential/horizontal \beta such that the tangential velocity is v_\perp ~ = ~ v \cos( \beta ) ). The vector and the center of the Earth define a plane. Decompose the velocity vector into a radial and a tangential component in that plane. First, we find the semimajor axis:

\large a ~=~ { \huge { 1 \over { { 2 \over r } - { v^2 \over \mu } } } }

Next, compute the angular momentum:

\large L ~=~ r v ~ \cos( \beta )

Compute the eccentricity:

\large e ~=~ \sqrt{ 1 - {\LARGE {{ L^2 } \over { \mu a }} } }

apoapse ~=~ \large ( 1 + e ) a ~~~~~~ periapse ~=~ \large ( 1 - e ) a

### Changing perigee by changing apogee velocity

\large v_a^2 = 2 \mu \LARGE \left( { 1 \over r_a } - { 1 \over {r_a + r_p} } \right) ~ ~ ~ ~ ~ ~ \LARGE { { \partial v_a } \over { \partial r_p } } = { \mu \over { v_a ( r_a + r_p )^2 } } ~ ~ ~ ~ ~ ~ for nearly circular orbits: ~ ~ ~ \LARGE { { \partial v } \over { \partial r } } \approx { v \over { 4 r } }

### Fictional Forces in Orbit

In the rotating frame of a circular orbit, counterclockwise viewed from above the orbital plane, the directions are

 direction unit vector description x \vec i Tangential to (along the line of) the orbit, in the orbital plane, pointing clockwise or westward y \vec j Radially outwards from the center of rotation, in the orbital plane z \vec k Perpendicular to the orbital plane, northwards

The rotation is expressed as \vec \Omega = \omega \vec k , where \omega is the angular velocity of the orbit . The radial vector \vec r is composed of \vec r = x \vec i + y \vec j + z \vec k .

Coriolis acceleration: \large \ddot{\vec r}_{Coriolis} = -2 \vec \Omega \times \dot { \vec r }

Centrifugal acceleration: \large \ddot{\vec r}_{Centrifugal} = - \vec \Omega \times \vec \Omega \times \vec r

FROM HERE DOWN, WORK IN PROGRESS, NOT VERIFIED:

• note - these are probably the Hill-Clohessy-Wiltshire equations

Centripedal (gravity) acceleration: \large \ddot{\vec r}_{Centripedal} = \omega^2 ( 2 y \vec k - x \vec i - z \vec j )

Scalar equations:

\large \ddot x = 2 \omega \dot y

\large \ddot y = -2 \omega \dot x + 3 \omega^2 y

\large \ddot z = -\omega^2 z

### Locus of Elliptical Orbit Position in Rotating Frame

For small eccentricities e, the deviation of the position of an object in a nearly circular eccentric orbit deviates from a ideal circular orbit as an ellipse, with a width of 4e and a height of 2e. This is difficult to compute analytically, but easy to show numerically. Here is a plot the normalized loci of the x,y position in the rotating frame, for various values of eccentricity:

If the whole orbit rotates east, clockwise when viewed from the north, then the object follows the locus above clockwise, with \theta = 0 at the bottom of the ellipsoid.

The figure is very close to an ellipse for small e, but not exactly so. The program computes the radial distance rr, and the radial position xr and yr as a function of \theta. The program then computes the eccentric anomaly E, and the mean anomaly M. It then rotates the position vector back along the orbit, to approximately vertical, then subtracts the unit vector representing the elliptical orbit. So, it is approximately like watching an object in an elliptical orbit from a position in a circular orbit with the same semimajor axis. The deviation from an ellipse is quite small, until the eccentricity gets larger than 0.01 or so. Server sky orbits will have eccentricities of less than 0.002 .

In the rotating frame, these eccentric loci describe the path of an object subject to fictitious forces. This provides an additional check on our equations for fictitious forces.

#### The math

\large \dot{ \theta } = v_{\perp} / r = v_0 ( 1+e \cos( \theta )) / ( a (1-e^2) / {1+e\cos(\theta)}

\large \dot{ \theta } = ( \sqrt{ \mu / ( a (1 - e^2) ) } / a ( 1-e^2 ) ) ( 1 + e\cos( \theta ))^2

\large \dot{ \theta } = ( \sqrt{ \mu / ( a^3 (1 - e^2)^3 ) } ( 1 + 2 e \cos( \theta ) + e^2 \cos( \theta )^2 )

for small perturbations, e^2 \approx 0 , so

\large \dot{ \theta } \approx ( \sqrt{ \mu / a^3 } ( 1 + 2 e \cos( \theta ) )

In the rotating frame, \dot{ x } \approx a ( \dot{ \theta } - \omega ) where \omega \equiv \sqrt{ \mu / a^3 } , so

\large \dot{ x } \approx a \sqrt{ \mu / a^3 } ( ( 1 + 2 e \cos( \theta ) - 1 )

\large \dot{ x } \approx 2 e a \omega ( \cos( \theta ) )

Approximating \theta \approx \omega t , we can integrate to get:

\Large x \approx -2 e a \sin( \theta )

\large \dot{ y } = v_r = e v_0 \sin( \theta ) \approx e a \omega \sin( \omega t ) Integrating:

\Large y \approx -e a \cos( \theta )

For small e , these equations in y and x describe the locus calculated above.

#### Testing the Equations for Acceleration

\large \ddot x ~ ? = ~ \large 2 \omega \dot y

\large \ddot x = { { d^2 } \over { dt^2 } } ( -2 e a \sin( \theta ) ) = { d \over { dt } } ( -2 e a \omega \cos( \theta ) ) = \Large 2 e a \omega^2 \sin ( \theta )

\large 2 \omega \dot y = 2 \omega { d \over { dt } } -e a \cos( \theta ) = \Large 2 e a \omega^2 \sin ( \theta ) . . . equal!

\large \ddot y ~ ? = ~ \large -2 \omega \dot x + 3 \omega^2 y

\large \ddot y = { { d^2 } \over { dt^2 } } ( -e a \cos( \theta ) ) = { d \over { dt } } ( e a \omega \sin( \theta ) ) = \Large e a \omega^2 \cos( \theta )

\large -2 \omega \dot x + 3 \omega^2 y = -2 \omega { d \over { dt } }( -2 e a \sin( \theta ) + 3 \omega^2 ( - e a \cos( \theta ) ) )

\large ~~~~~~~~~~~~~~= 4 e a \omega^2 \cos(\theta) - 3 e a \omega^2 \cos( \theta ) = \Large e a \omega^2 \cos( \theta )~~~ ... equal!

The acceleration equations work!

### Periods of M orbits

M orbits describe the number of minutes an orbit takes travel once around the earth and return to the same position overhead. For server sky, these are integer fractions of a 1440 minute synodic day; this makes it easier to calculate the sky position given the orbital parameters and the time of day. the M288 orbit returns to the same apparent position 5 times per day, or 365.256...*5 times per year. That position moves around the earth 365.256...+1 times per year. So the total number of orbits per year, relative to the stars, is 365.256...*6+1 orbits per year. That is divided into the year length in seconds to yield the

M288 sidereal orbit time = ( 365.256... * 86400 ) / ( 365.256... * 6 + 1 ) = 86400 / ( 6 + 1/365.256... ) = 14393.43227 seconds

1 year = 365.256363004 days of 86,400 seconds, or 31558149.7635456 seconds.

J2 speedup fraction = - 3 J_2 ( a_E / a )^2 = 3 \times 1.082626683e-3 \times (6378107m)^2 / a^2 = 1.321245688e11m^2 / a^2

### A Table of orbits

 LEO 300Km M288 M360 GEO Moon Earth units \mu gravitation param. 3.98600448e14 1.3271244e20 m3/s2 relative to earth Sun J_2 Oblate-ness -1.082626683e-3 earth radius = 6378107m -6e-7 \omega'/\omega J2 speedup fraction 2.9627e-3 8.0782e-4 6.3356e-4 7.4318e-5 8.9417e-7 2e-17 a_g gravity 8.938095 2.437062 1.9113693 0.02242078 0.002697573 0.005930053 s T sidereal period 5431.010 14393.4323 17270.5433 86164.100 2360591.577 31558149.76 s T_s synodic period 5431.945 14400 17820 86400 2551442.9 31558149.76 s T/2\pi Sidereal / 2pi 864.3721 2290.78585 2748.69228 13713.44093 375698.7212 5022635.5297 s \omega Angular velocity 1.1569e-03 4.36531e-04 3.63809e-04 7.29212e-05 2.66171e-06 1.99099e-07 rad/s orbits/year 5810.733 2192.5382 1827.2819 366.25640 13.36879 1.00000 a semimajor axis 6678000 12788971 14440980 42164170 384399000 1.4959826e11 m R_a apogee radius 6678000 12838976 14440980 42164170 405696000 1.5209823e11 m R_p perigee radius 6678000 12738976 14440980 42164170 363104000 1.4709829e11 m e eccentricity 0.000000 0.001951 0.001728 0.000000 0.055401 0.016711 V_0 mean velocity 7725.84 5582.79 5253.76 3074.66 1023.16 29784.81 m/s V_a apogee velocity 7725.84 5571.90 5244.68 3074.66 966.47 29287.07 m/s V_p perigee velocity 7725.84 5593.68 5262.84 3074.66 1079.84 30282.55 m/s C_3 orb. specific energy -59688597 -31167516 -27602035 -9453535 -1036945 -887125553 J/kg

Note: This table uses the classic formula \omega^2 a^3 = \mu , and does not take into account the oblate spheroid shape of the Earth, and many other perturbations. However, with the perturbations included, and with good data from ground stations and GPS to establish positions and velocities, we really can compute these numbers to this many decimal places. So while the numbers above are actually far less accurate, they represent the precision of the measurements we will someday compute.

The eccentricities for the M orbits assume orbits mapped onto a 50km minor radius toroid.

LAGEOS 1 and LAGEOS 2 are two slightly lower satellites in inclined but highly circular orbits.

REFS:

copied from http://server-sky.com/NearCircularOrbits

NearCircularOrbitsOlder (last edited 2020-04-18 23:01:44 by KeithLofstrom)