|
Size: 1595
Comment:
|
Size: 1595
Comment:
|
| Deletions are marked like this. | Additions are marked like this. |
| Line 6: | Line 6: |
| ||<)> > m ||<)> m || ||<)> hc ||<)> m³ || | ||<)> > m ||<)> m || ||<)>hectare||<)> m³ || |
NEO Settlement
Start with this claim in Near-Earth Objects by Yeomans: 1000 NEOs larger than 1000 meters, 1e6 NEOs larger than 30 meters. Assume a power law of quantity versus size (assume spherical, a lousy assumption).
diameter |
radius |
quantity |
area |
volume |
|
> m |
m |
|
hectare |
m³ |
|
31.6 |
15.8 |
1000000 |
0.314 |
1.66e4 |
from Yeomans |
100 |
50 |
100000 |
3.140 |
5.24e5 |
|
316 |
158 |
10000 |
31.40 |
1.66e7 |
|
1000 |
500 |
1000 |
314 |
5.24e8 |
from Yeomans |
3160 |
1580 |
100 |
3140 |
1.66e10 |
|
10000 |
5000 |
10 |
31400 |
5.24e11 |
|
31600 |
15800 |
1 |
314000 |
1.66e13 |
The quantity is the cumulative sum of all objects larger than that radius (or area or volume). Assume a power law for the cumulative quantity versus area A in hectares, N(A) = 314000/A, and dN/dA = n(A) = -314000/A². Assume a minimum usable area of A₀ (perhaps , and a maximum area A₁ for 314000 hectare for 1 large NEO asteroid.
Assume a cylindrical small habitat, 25 meters radius, 25 meters across, 6 RPM and 1 gee. Surface area is 2π*(25m)² = 3930m² = 0.97 acres; assume day/night cycle rotation of solar illumination and green photon recycling as red to produce the photosynthetic equivalent of 5 acres. Assume 4 meters of shielding, about 16000 m³ of asteroid material made into one habitat.
Fit