Differences between revisions 15 and 16
 ⇤ ← Revision 15 as of 2021-07-16 08:01:20 → Size: 1145 Editor: KeithLofstrom Comment: ← Revision 16 as of 2021-07-16 08:01:36 → ⇥ Size: 1140 Editor: KeithLofstrom Comment: Deletions are marked like this. Additions are marked like this. Line 10: Line 10: || $day$ || 86400 || sec || solar day (longer than sidereal day || || $day$ || 86400 || sec || solar day (longer than sidereal day || Line 14: Line 14: For an For an

# E < μ/r

Climbing out of the Earth's gravity well requires energy, but a launch loop on the rotating Earth can launch to infinity with less than the classical μ/r gravitational escape energy. The difference is taken from the rotational energy of the Earth itself.

 \large G 6.67408e-11 m³/kg/s² Gravitational constant \large M 5.972e+24 kg Mass of Earth \large \mu 398600 km³/s² Standard gravitational parameter of Earth \large R 6378 km Equatorial radius of Earth day 86400 sec solar day (longer than sidereal day

and surface radius \large R . The standard gravitational parameter \large \mu for the planet is the product of the gravitational constant \large G and \large M : \large \mu ~=~ G M . The gravity at the surface of the planet is \large g(R) ~=~ \mu / R^2 , and the gravity at radius \large r above the surface is \large g(r) ~=~ \mu / r^2 .

For an

E<μ÷r (last edited 2021-07-17 07:19:46 by KeithLofstrom)