Differences between revisions 15 and 16
Revision 15 as of 2021-07-16 08:01:20
Size: 1145
Comment:
Revision 16 as of 2021-07-16 08:01:36
Size: 1140
Comment:
Deletions are marked like this. Additions are marked like this.
Line 10: Line 10:
|| $ day $ || 86400 || sec || solar day (longer than sidereal day ||     || $ day $ || 86400 || sec || solar day (longer than sidereal day ||
Line 14: Line 14:
For an  For an

E < μ/r

Climbing out of the Earth's gravity well requires energy, but a launch loop on the rotating Earth can launch to infinity with less than the classical μ/r gravitational escape energy. The difference is taken from the rotational energy of the Earth itself.

\large G

6.67408e-11

m³/kg/s²

Gravitational constant

\large M

5.972e24

kg

Mass of Earth

\large \mu

398600.4418

km³/s²

Standard gravitational parameter of Earth

\large R

6378

km

Equatorial radius of Earth

day

86400

sec

solar day (longer than sidereal day

and surface radius \large R . The standard gravitational parameter \large \mu for the planet is the product of the gravitational constant \large G and \large M : \large \mu ~=~ G M . The gravity at the surface of the planet is \large g(R) ~=~ \mu / R^2 , and the gravity at radius \large r above the surface is \large g(r) ~=~ \mu / r^2 .

For an

E<μ÷r (last edited 2021-07-17 07:19:46 by KeithLofstrom)