Differences between revisions 6 and 7
Revision 6 as of 2016-12-12 02:17:16
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Revision 7 as of 2016-12-13 01:15:15
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Eq 23: $ T_r = T \left( 1 + { { \gamma-1 } \over 2 } M^2 \right) \approx { { \gamma-1 } \over 2 } M^2 T $ Allen/Eggers Eq 23: $ T_r = T \left( 1 + { \Large { { \gamma-1 } \over 2 } } M^2 \right) \approx { \Large { { \gamma-1 } \over 2 } } M^2 T $ for high mach numbers
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Eq 25: $ ( T_r - T_w) = V^2 / 2 C_p $ ... since $ V_{sound} = \sqrt{ ( \gamma - 1 ) C_p T } $ . at altitude. Allen/Eggers Eq 25: $ ( T_r - T_w ) = V^2 / 2 C_p $ ... since $ V_{sound} = \sqrt{ ( \gamma - 1 ) C_p T } $ . at altitude.
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Eq 26: $ h = { 1 \over 2 } ~ C_f ~ C_p ~ \rho ~ V $ Heat transfer coefficient (all subcripted $._l$ in the original) . Allen/Eggers Eq 26: $ h = { 1 \over 2 } ~ C_f ~ C_p ~ \rho ~ V $ Heat transfer coefficient (all subcripted $._l$ in the original) .
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Eq 42a(?): $ \Large { { d H_s } \over { d t } } = { { N_{ur} k_r ( T_r - T_w ) } \over \sigma } \approx { { N_{ur} k_r T_r } \over \sigma } $ Heat transfer rate per unit area at the stagnation point Allen/Eggers Eq 42a(?): $ \Large { { d H_s } \over { d t } } = { { Nu_r k_r ( T_r - T_w ) } \over \sigma } $ Heat transfer rate per unit area at the stagnation point
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Eq 42b(?): $ Nu_r = 0.934 ~ Re_{\sigma}^{0.5} ~ Pr^{ 0.4 } $ Nusselt number at recovery temperature (unitless) Allen/Eggers Eq 42b(?): $ Nu_r = 0.934 ~ Re_{\sigma}^{0.5} ~ Pr^{ 0.4 } $ Nusselt number at recovery temperature (unitless)
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The Prandtl number is assumed to be unity, so
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Eq KHL1: $ ~ Nu_r = 0.934 ~ Re_{\sigma}^{0.5} $ = 0.934 $ ~ \Large \sqrt{ { \rho ~ V ~ \sigma } \over \mu_r } $
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Eq KHL2: $ ~ { \Large { { d H_s } \over { d t } } } = $ 0.934 $ ~ { \Large \sqrt{ { \rho ~ V ~ \sigma } \over \mu_r } ~ { { k_r V^2 } \over { 2 C_p \sigma } } } ~ = ~ $ 0.467 $ ~ { \Large \sqrt{ { \rho ~ V } \over { \mu_r ~ \sigma } } ~ { { k_r V^2 } \over { C_p } } } $
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From the definition of the Prandtl number in ''Hypersonic and High Temperature Gas Dynamics'' by Anderson (1989)

Eq 16.42: $ ~ Pr ~=~ \mu C_p / k_T $ ( assumed 1 ), we can infer

Eq KHL3: $ ~ k_r = k_T ~=~ \mu C_p ~=~ \mu_r C_p ~=~ $ 1.03e-6 $ ~ V ~ \sqrt{ C_p } $

Eq KHL4: $ ~ { \Large { { d H_s } \over { d t } } } ~ = ~ $ 0.467 $ ~ { \Large \sqrt{ { \rho ~ V } \over { \mu_r ~ \sigma } } ~ { {\mu_r C_p V^2 } \over { C_p } } } ~ = ~ $ 0.467$ ~ { \Large \sqrt{ { \rho ~ V \mu_r } \over { \sigma } } } ~ V^2 $

The Allen/Eggers paper gives a fps expression for the coefficient of thermal velocity $ \mu_r $ without citing a source. The book ''Hypersonic and High Temperature Gas Dynamics'' by Anderson (1989) has provides this equation on page 605 in section 16.6 ''Transport Properties for High Temperature Air'':

Eq And1: $ ~ \mu_0 = $ 1.462e-5 $ ~ { \large { gm \over { cm ~ s ~ K^{1/2} } } } ~ { \Large { T^{1/2} \over { 1 + 112/T } } } $

Let's assume $ \mu_0 = \mu_r $ (hm...) and simplify the demominator (making the viscosity a wee bit larger) and convert it to mks:

Eq KHL5: $ ~ \mu_r = $ 1.462e-6 $ ~ { \large { kg \over { m ~ s ~ K^{1/2} } } } ~ T^{1/2} $

Now let's assume $ T \approx ~ T_r - T_w $ and use Eq 25:

Eq KHL6: $ ~ \mu_r = $ 1.462e-6 $ ~ V / \sqrt{ 2 C_p } ~= $ 1.03e-6 $ ~ V / \sqrt{ C_p } $

Combining KHL4 and KHL6:

Eq KHL7: $ ~ { \Large { { d H_s } \over { d t } } } ~ = ~ $ 0.467 $ ~ { \Large \sqrt{ { \rho ~ 1.03e-6 ~ { V^2 } } \over { \sqrt{ C_p } \sigma } } } ~ V^2 ~ = ~ $ 4.74e-4 $ ~ { \Large \sqrt{ \rho \over \sigma } } ~ V^3 ~ C_p^{-1/4} $

Except for the last factor of $ C_p^{-1/4} $, this resembles equation 44 in the Allen/Eggers paper:

Allen/Eggers Eq 44: $ ~ { \Large { { d H_s } \over { d t } } } ~=~ $ 6.8e-6 $ ~ { \Large \sqrt{ \rho \over \sigma } } ~ V^3 $ in foot-slug-second-BTU units.

So, where is the discrepancy?

 

Allen/Eggers Hypersonic Drag, 1957

In METRIC!


Symbols:

$ T_r

Kelvins

Recovery temperature

T_w

Kelvins

Wall temperature (relatively small, will be ignored)

T

Kelvins

Temperature at altitude

M

unitless

Mach number at altitude

H

J / m2

Heat transferred per unit area

h

J / m2 - K

Heat transfer coefficient

C_v

J / kg K

Specific heat capacity at constant volume

C_p

J / kg K

Specific heat capacity at constant pressure

C_f

?

Skin effect coefficient

\gamma

C_p / C_v

Specific heat capacity ratio, typically 1.4

\sigma

meters

nose radius

k_r

?

Thermal conductivity at the recovery temperature

Nu_r

unitless

Nusselt number

Re_{\sigma}

unitless

Reynolds number for nose cone radius \sigma

Pr

unitless

Prandtl number = 1

\mu_r

?

coefficient of viscosity at the recovery temperature

  • note 1: in the original document, many variables have subscript ._l indicating "local" or at altitude, a complication not needed here

  • note 2: \gamma can be higher for diatomic or ionized gasses.

Assuming that the Prandtl number is unity.

Allen/Eggers Eq 23: T_r = T \left( 1 + { \Large { { \gamma-1 } \over 2 } } M^2 \right) \approx { \Large { { \gamma-1 } \over 2 } } M^2 T for high mach numbers

Allen/Eggers Eq 25: ( T_r - T_w ) = V^2 / 2 C_p ... since V_{sound} = \sqrt{ ( \gamma - 1 ) C_p T } . at altitude.

Allen/Eggers Eq 26: h = { 1 \over 2 } ~ C_f ~ C_p ~ \rho ~ V Heat transfer coefficient (all subcripted ._l in the original) .

  • .. much omitted ...

Page 17: (modified to ditch minus sign)

Allen/Eggers Eq 42a(?): \Large { { d H_s } \over { d t } } = { { Nu_r k_r ( T_r - T_w ) } \over \sigma } Heat transfer rate per unit area at the stagnation point

Page 18:

Allen/Eggers Eq 42b(?): Nu_r = 0.934 ~ Re_{\sigma}^{0.5} ~ Pr^{ 0.4 } Nusselt number at recovery temperature (unitless)

"note that???" Re_{\sigma} ~ = ~ \rho ~ V ~ \sigma / \mu_r

The Prandtl number is assumed to be unity, so

Eq KHL1: ~ Nu_r = 0.934 ~ Re_{\sigma}^{0.5} = 0.934 ~ \Large \sqrt{ { \rho ~ V ~ \sigma } \over \mu_r }

Eq KHL2: ~ { \Large { { d H_s } \over { d t } } } = 0.934 ~ { \Large \sqrt{ { \rho ~ V ~ \sigma } \over \mu_r } ~ { { k_r V^2 } \over { 2 C_p \sigma } } } ~ = ~ 0.467 ~ { \Large \sqrt{ { \rho ~ V } \over { \mu_r ~ \sigma } } ~ { { k_r V^2 } \over { C_p } } }

From the definition of the Prandtl number in Hypersonic and High Temperature Gas Dynamics by Anderson (1989)

Eq 16.42: ~ Pr ~=~ \mu C_p / k_T ( assumed 1 ), we can infer

Eq KHL3: ~ k_r = k_T ~=~ \mu C_p ~=~ \mu_r C_p ~=~ 1.03e-6 ~ V ~ \sqrt{ C_p }

Eq KHL4: ~ { \Large { { d H_s } \over { d t } } } ~ = ~ 0.467 ~ { \Large \sqrt{ { \rho ~ V } \over { \mu_r ~ \sigma } } ~ { {\mu_r C_p V^2 } \over { C_p } } } ~ = ~ 0.467 ~ { \Large \sqrt{ { \rho ~ V \mu_r } \over { \sigma } } } ~ V^2

The Allen/Eggers paper gives a fps expression for the coefficient of thermal velocity \mu_r without citing a source. The book Hypersonic and High Temperature Gas Dynamics by Anderson (1989) has provides this equation on page 605 in section 16.6 Transport Properties for High Temperature Air:

Eq And1: ~ \mu_0 = 1.462e-5 ~ { \large { gm \over { cm ~ s ~ K^{1/2} } } } ~ { \Large { T^{1/2} \over { 1 + 112/T } } }

Let's assume \mu_0 = \mu_r (hm...) and simplify the demominator (making the viscosity a wee bit larger) and convert it to mks:

Eq KHL5: ~ \mu_r = 1.462e-6 ~ { \large { kg \over { m ~ s ~ K^{1/2} } } } ~ T^{1/2}

Now let's assume T \approx ~ T_r - T_w and use Eq 25:

Eq KHL6: ~ \mu_r = 1.462e-6 ~ V / \sqrt{ 2 C_p } ~= 1.03e-6 ~ V / \sqrt{ C_p }

Combining KHL4 and KHL6:

Eq KHL7: ~ { \Large { { d H_s } \over { d t } } } ~ = ~ 0.467 ~ { \Large \sqrt{ { \rho ~ 1.03e-6 ~ { V^2 } } \over { \sqrt{ C_p } \sigma } } } ~ V^2 ~ = ~ 4.74e-4 ~ { \Large \sqrt{ \rho \over \sigma } } ~ V^3 ~ C_p^{-1/4}

Except for the last factor of C_p^{-1/4} , this resembles equation 44 in the Allen/Eggers paper:

Allen/Eggers Eq 44: ~ { \Large { { d H_s } \over { d t } } } ~=~ 6.8e-6 ~ { \Large \sqrt{ \rho \over \sigma } } ~ V^3 in foot-slug-second-BTU units.

So, where is the discrepancy?

MoreLater

DragAllenEggers1957 (last edited 2016-12-13 04:48:32 by KeithLofstrom)